# How do you convert 0.02 g/mL to the unit g/L?

$0.02 \cdot g \cdot m {L}^{-} 1 = 2 \times {10}^{-} 5 \cdot g \cdot {L}^{-} 1$
$0.02 \cdot g \cdot m {L}^{-} 1 = 2 \times {10}^{-} 2 \cdot g \cdot m {L}^{-} 1$ $=$
$=$ $2 \times {10}^{-} 2 \cdot g \cdot \times {10}^{-} 3 \cdot {L}^{-} 1$
$= 2 \times {10}^{-} 5 \cdot g \cdot {L}^{-} 1$