How do you convert 1.05 atm of pressure to its equivalent in millimeters of mercury?

2 Answers
Apr 15, 2016

Answer:

#1.05 cancel("atm") *( 760. "mm-Hg")/(1 cancel("atm"))= 798" mm-Hg"#

Explanation:

The method of doing this conversion depends on what specific information we have at hand. I'll do the conversion two different ways to show what I mean. This answer has the direct version, and the next will have a two-step version.

First, lets assume that we have measurement or reference for atm in terms of mm-Hg. In this case we can look up the value of mm-Hg for 1 atm (Atmosphere (unit) ):

# 1 " atm" = 760. "mm-Hg"#

Then we can turn this into a conversion factor:

#(1 " atm") /( 760. "mm-Hg")# or #( 760. "mm-Hg")/(1 " atm")#

We can now apply the conversion by starting with the unit we have, and selecting the factor that cancels that unit and leaves the one we want:

#1.05 cancel("atm") *( 760. "mm-Hg")/(1 cancel("atm"))= 798" mm-Hg"#

Apr 15, 2016

Answer:

#1.05 cancel("atm") * (( 101.3 cancel("kPa"))/(1 cancel("atm")))*( (7.501 " mm-Hg")/( 1 cancel("kPa")))= 798" mm-Hg"#

Explanation:

The method of doing this conversion depends on what specific information we have at hand. I'll do the conversion two different ways to show what I mean. This answer is the two-step version.

# 1 " atm" = 101.3 " kPa"#
# 1 " kPa" = 7.501" mm-Hg"#

Then we can turn these into conversion factors:

#(1 " atm") /( 101.3 " kPa")# and #( 1 " kPa")/(7.501 " mm-Hg")#

We can now apply the conversion by starting with the unit we have, and selecting the factor that cancels that unit and leaves the one we want. We sometimes need to flip the factors over to get the correct units in the numerator and the denominator, but that's simple:

#1.05 cancel("atm") * (( 101.3 cancel("kPa"))/(1 cancel("atm")))*( (7.501 " mm-Hg")/( 1 cancel("kPa")))= 798" mm-Hg"#