# How do you convert 190 mm Hg to atmospheres of pressure?

Mar 12, 2016

We know that $1$ $\text{atmosphere}$ pressure will support a column of mercury $760$ $m m$ $H g$ in length. The pressure is simply the fraction.

#### Explanation:

So $\text{Atmospheres of pressure}$ $=$ "190 mm Hg"/("760 mm Hg" *(atm^-1)) $=$ $\frac{19}{76}$ $\text{atmospheres}$.

Mar 12, 2016

$= 0.25 a t m$
So pressure of 190 mm of Hg $= \frac{1}{760} \times 190 a t m = 0.25 a t m$