How do you convert 2.54 moles magnesium carbonate to formula units?

1 Answer
anor277
Apr 18, 2016

By use of #"Avogadro's Number", N_A=6.022xx10^23*mol^-1#

Explanation:

It is a fact that in #1# #mol# of stuff there are #6.022xx10^23# individual items of that stuff.

Thus in #2.54# #mol# #MgCO_3#, there are #2.54# #xx# #N_A# individual formula units. What is the mass of this quantity?

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