# How do you convert 4.00 moles of N_2 to liters?

First we assume a temperature and pressure; the molar volume at $R T$ and $1$ $a t m$ is $25.4$ ${\mathrm{dm}}^{3}$ $m o {l}^{-} 1$. We get a volume of slightly over $100$ $L$.
$4 \cdot m o l \times 25.4$ ${\mathrm{dm}}^{3}$ $m o {l}^{-} 1$ or $4 \cdot m o l \times 25.4$ $L$ $m o {l}^{-} 1$ ($1 L = 1 \cdot {\mathrm{dm}}^{3}$) $=$ ??" litres"