How do you convert 4,300 g of mercury into moles?

1 Answer
Jan 20, 2017

Answer:

#"No. of moles"# #=# #"Mass"/"Molar mass"#

Explanation:

And here,

#"No. of moles"# #=# #(4300*g)/(200.6*g*mol^-1)~=21*mol#

#"Density", rho_"Hg"=13.5*g*mL^-1#. What is the volume of this mass?