# How do you convert 4,300 g of mercury into moles?

Jan 20, 2017

$\text{No. of moles}$ $=$ $\text{Mass"/"Molar mass}$
$\text{No. of moles}$ $=$ $\frac{4300 \cdot g}{200.6 \cdot g \cdot m o {l}^{-} 1} \cong 21 \cdot m o l$
$\text{Density", rho_"Hg} = 13.5 \cdot g \cdot m {L}^{-} 1$. What is the volume of this mass?