How do you convert 64.1 g of aluminum to moles?

May 31, 2018

Your Periodic Table will tell you that it is $27.0 \cdot g \cdot m o {l}^{-} 1$...
And so we take the quotient...$\frac{64.1 \cdot g}{27.0 \cdot g \cdot m o {l}^{-} 1} = 2.37 \cdot m o l$