How do you convert $(8.3, 4.2)$ into polar forms?

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Answer 1 · 2016-01-29T13:46:08

$(9.302,0.149pi)$

suppose,
$x=8.3$
$y=4.2$
now, we know,
for polar form,
$r^2=x^2+y^2$

$or,r=root(2)(x^2+y^2)$

now, by putting the value of x and y in the equation, we get

$r=root(2)(8.3^2+4.2^2$

$=root(2)(86.53)$

$=9.302$

again
we know,
$theta=tan^(-1)(y/x)$

by putting the value of x and y on the above equation, we get,

$theta=tan^(-1)(4.2/8.3)$

$=0.149pi$

so, the polar form is ( $9.302,0.149pi$ )

How do you convert (8.3, 4.2)(8.3, 4.2) into polar forms?