Question

How do you convert (9, 0) into polar coordinates?

Answer 1

This coordinate lies on the y-axis at the point `x=9 and y=0` in Quadrant I . Therefore, `theta=0^o`

Explanation:

Now, `r=sqrt(x^2+y^2)=sqrt(9^2+0^2)=9`

polar coordinate `=(r,theta)=(9,0^o)`

hope that helped