How do you convert 9.45 moles g of #Al_2O_3# into grams of #Al_2O_3#?

1 Answer
Dec 9, 2015

Answer:

#963.9g#

Explanation:

consider the relationship between the number of moles, molar mass and the mass of a compound,

#n= m/M#

where n is the number of moles, m is the mass of the compound and M is the molar mass of the compound.

you just have to multiply the number of moles (9.45 moles) by the molar mass of #Al_"2"O_"3"# which is #27*2+16*3 = 102#

so,
# m = 9.45 mol * 102gmol ^"-1" #

#m = 963.9g#