How do you convert the Cartesian coordinates (-3, -2) to polar coordinates?

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Answer 1 · 2015-10-19T01:36:28

#P~=3.6/_213.69^(o)#

It is in the third quadrant so, the angle #180^(o) < phi<270^(o)#

The module is:

#m^2=3^2+2^2#

#m^2=9+4#

#m=sqrt(13)~=3.6#

The angle is:

#phi=tan^-1(2/3) +180#

#phi~=213.69^(o)#

#P~=3.6/_213.69^(o)#