# How do you convert the complex the number into polar representation: 2 sqrt(3) + 2i?

Jul 15, 2016

$= 4 {e}^{i \frac{\pi}{6}}$

#### Explanation:

$2 \sqrt{3} + 2 i$

$= 4 \left(\frac{\sqrt{3}}{2} + \frac{i}{2}\right)$

$= 4 \left(\cos \left(\frac{\pi}{6}\right) + i \sin \left(\frac{\pi}{6}\right)\right)$

$= 4 {e}^{i \frac{\pi}{6}}$