# How do you covert 7 L to ml?

$1 \cdot m L = {10}^{-} 3 \cdot L$ or $1 \cdot L = {10}^{3} \cdot m L$
And thus $\frac{7 \cdot \cancel{L}}{{10}^{-} 3 \cdot \cancel{L} \cdot m L}$ $=$ $7000 \cdot m L$