How do you cube a matrix #([2, -1], [3, 1])#?

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Answer 1 · 2018-07-30T09:09:55

The answer is #=((-7,-4),(12,-11))#

If you have a matrix #A#

The cube is

#=A^3=A^2*A#

Here,

#A=((2,-1),(3,1))#

Therefore,

#A^2=A*A=((2,-1),(3,1))*((2,-1),(3,1))#

#=((1,-3),(9,-2))#

#A^3=A^2*A=((1,-3),(9,-2))*((2,-1),(3,1))#

#=((-7,-4),(12,-11))#