How do you decompose #(-4y)/(3y^2-4y+1)# into partial fractions?
Please see the explanation for the process. The answer is:
Factor the denominator
Write the equation of the partial fractions with the unknowns, A and B:
Multiply both sides by the denominator:
Make B disappear by setting y = 1:
#A = -2
Substitute - 2 for A and set y = 0: