How do you derive #g=(Gm)/r^2# and #V=-(Gm)/r#?

1 Answer
Candy
Jan 28, 2018

Here you go....

Explanation:

Weight of an object on Earth = Gravitational force exerted on an object by the Earth.
Let us consider a body having mass "m".
#mg=G*(mM)/R^2#
where,
g=acceleration due to gravity,
G=Gravitational constant,
M=Mass of the Earth,
and R=radius of the Earth.
Weight of the body (on Earth)=
mass#(m)*#gravitational acceleration#(g)#
Cancel out the #m# on both sides to get:
#g=G*M/R^2=(GM)/R^2#

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