How do you describe the transformation in #y = (2x + 1)^2 - 2#?

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Answer 1 · 2017-11-26T02:12:51

First you factor, and then describe the transformation.

In the equation, #(2x+1)# first has to be factored.

Just factor out the two from the equation, and you are left with:
#y=4(x+1/2)^2-2#

Now you describe the transformation:

First, there is vertical stretch by factor of #4# in the first part of your new equation

#y= ul(4) (x+1/2)^2-2#

Second, there is a horizontal translation right #1/2# units in your new equation.

#y= 4(x + ul(1/2)) -2#

Finally, there is a vertical translation down #2# units in both new and old equations.

#y= 4(x + 1/2) - ul(2)#