How do you describe the transformation in $y = (2x + 1)^2 - 2$ ?

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Answer 1 · 2017-11-26T02:12:51

First you factor, and then describe the transformation.

In the equation, $(2x+1)$ first has to be factored.

Just factor out the two from the equation, and you are left with:
$y=4(x+1/2)^2-2$

Now you describe the transformation:

First, there is vertical stretch by factor of $4$ in the first part of your new equation

$y= ul(4) (x+1/2)^2-2$

Second, there is a horizontal translation right $1/2$ units in your new equation.

$y= 4(x + ul(1/2)) -2$

Finally, there is a vertical translation down $2$ units in both new and old equations.

$y= 4(x + 1/2) - ul(2)$

How do you describe the transformation in y = (2x + 1)^2 - 2y = (2x + 1)^2 - 2?