How do you determine if absx|x| is an even or odd function?

1 Answer
May 30, 2016

abs(x)|x| is an even function.

Explanation:

A function f(x)f(x) is even if f(-x) = f(x)f(x)=f(x) for all xx in its domain.

A function f(x)f(x) is odd if f(-x) = -f(x)f(x)=f(x) for all xx in its domain.

In our example, we have:

abs(-x) = abs(x)|x|=|x|

for any value of xx.

So abs(x)|x| is an even function.