Question

How do you determine if `f(x) = 0.7x^2 + 3` is an even or odd function?

Answer 1

Even function

Explanation:

We have: `f(x) = 0.7 x^(2) + 3`

For a function, if `f(x) = f(- x)`, then it is said to be even.

`=> f(- x) = 0.7 (- x)^(2) + 3`

`=> f(- x) = 0.7 x^(2) + 3`

Therefore, the function is even.