Question

How do you determine if `f(x) = 0.8x^3` is an even or odd function?

Answer 1

Odd.

Explanation:

We have: `f(x) = 0.8 x^(3)`

A function is odd if `f(- x) = - f(x)`:

`=> f(- x) = 0.8 (- x)^(3)`

`=> f(- x) = 0.8 cdot - x`

`=> f(- x) = - 0.8`

Therefore, the function is odd.