Question

How do you determine if `f(x)=1/(x^3+x)^5` is an even or odd function?

Answer 1

Odd

Explanation:

f is even or odd acording as `f(-x)=+-f(x)`.
Here, uxing `(-1)^n=-1`, for n = an odd integer,, `f(-x)=-f(x)`.
`f(-x)=1/((-x)^3+(-x))^5=1/((-1)^3(x^3+x))^5=1/(-1)^15f(x)=-f(x)`.