# How do you determine if f(x) = 2x^2 - 2 is an even or odd function?

Feb 18, 2017

Function is even

#### Explanation:

For an even function, $f \left(x\right) = f \left(- x\right)$. You can think of it as reflective symmetry about the y axis.

For an odd function, $f \left(x\right) = - f \left(- x\right)$. You can think of symmetry via a 180 rotation about the Origin.

Here: $f \left(- x\right) = 2 {\left(- x\right)}^{2} - 2 = 2 {x}^{2} - 2 = f \left(x\right)$.

So this function is even.