How do you determine if #f(x)= (-2x³)/(7x²+8)# is an even or odd function?

1 Answer
Jul 31, 2016

The function is odd.

Explanation:

To check if any function is even or odd (or none!), you simply have to evaluate it in #-x#. There are three possible scenarios:

  • If #f(-x)=f(x)#, then the function is even;
  • If #f(-x)=-f(x)#, then the function is odd;
  • If none of the two above is true, then the function is not even nor odd.

In this case, we have

#f(-x) = (-2(-x)^3)/(7(-x)^2+8)#

Since #(-x)^3=-x^3# and #(-x)^2=x^2#, the function becomes

#-(-2x^3)/(7x^2+8)#

which is exactly #-f(x)#! Thus, the function is odd.