Question

How do you determine if `f(x) = sin2x` is an even or odd function?

Answer 1

sin 2x is an odd function.

Explanation:

If `f(-x)=f(x)`, f(x) is even, and if f(-x)=-f(x), f(x) is odd.
`sin (2(-x)) =sin (-2x)=-sin 2x`