Question

How do you determine if `f(x)= (x^2 -1)/(2x)` is an even or odd function?

Answer 1

Odd.

Explanation:

An even function will satisfy the condition `f(-x) = f(x)`

An odd function will have `f(-x) = -f(x)`.

`f(-x) = ((-x)^2-1)/(2(-x)) = (x^2-1)/(-2x) = -(x^2-1)/(2x)`

`f(-x) = -f(x) implies` function is odd.