How do you determine if #f(x)= (x-3)^2# is an even or odd function?

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Answer 1 · 2016-06-21T19:23:05

An even function has the property that

#f(-x)=f(x)#

an odd function has the property that

#f(-x)=-f(x)#.

This function is neither even nor odd.

We can try with a value, for example #x=1#

#f(1)=(1-3)^2=(-2)^2=4#.

Now we try with #x=-1#

#f(-1)=(-1-3)^2=(-4)^2=16#

then none of the two conditions is verified.