How do you determine if # (sin(x)cos(x)) /( 2tan^2(x))# is an even or odd function?

Question

1485 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-24T14:07:28

See explanation.

To see if a function is odd or even you have to calculate #f(-x)#. Here you get:

#f(-x)=(sin(-x)*cos(-x))/(2tan^2(-x))=(-sinx*cosx)/(2tan^2x)=-f(x)#

The function satisfies a condition

#f(-x)=f(x)#

therfore it is an even function