How do you determine if x/(x^2 -1) is an even or odd function?
1 Answer
Jul 28, 2016
Explanation:
-
An even function is one for which
f(-x) = f(x) for allx in the domain. -
An odd function is one for which
f(-x) = -f(x) for allx in the domain.
In our example:
f(x) = x/(x^2-1)
f(-x) = (-x)/((-x)^2-1) = (-x)/(x^2-1) = -x/(x^2-1) = -f(x)
So
graph{x/(x^2-1) [-10, 10, -5, 5]}