How do you determine if xy=1 is an even or odd function?

1 Answer
Apr 24, 2016

I'm assuming that y is a function of x, so y(x)=1/x. This function is odd.

Explanation:

The easiest way to determine whether a function is even or odd is to evaluate y(-x) in terms of y(x), e.g.
y(-x)=1/(-x)=-(1/x)=-y(x)
and from the condition y(-x)=y(x) we see that our function is odd.

To fully understand this problem let's look at an example of an even function: y(x)=x^2.
y(-x)=(-x)^2=x^2=y(x)
Here, since y(-x)=y(x) this function is even.

Important notice: some functions, unlike integers, can be both odd and even (e.g. y(x)=0) or neither odd nor even (e.g. y(x)=x+1).