How do you determine if #xy=1# is an even or odd function?

1 Answer
Apr 24, 2016

I'm assuming that #y# is a function of #x#, so #y(x)=1/x#. This function is odd.

Explanation:

The easiest way to determine whether a function is even or odd is to evaluate #y(-x)# in terms of #y(x)#, e.g.
#y(-x)=1/(-x)=-(1/x)=-y(x)#
and from the condition #y(-x)=y(x)# we see that our function is odd.

To fully understand this problem let's look at an example of an even function: #y(x)=x^2#.
#y(-x)=(-x)^2=x^2=y(x)#
Here, since #y(-x)=y(x)# this function is even.

Important notice: some functions, unlike integers, can be both odd and even (e.g. #y(x)=0#) or neither odd nor even (e.g. #y(x)=x+1#).