How do you determine if #y= 1/x# is an even or odd function?

1 Answer
Aug 6, 2016

I'd say odd.

Explanation:

You can check by considering general rule:
ODD if: #f(-x)=-f(x)#
EVEN if: #f(-x)=f(x)#

So basically test a positive and a negative #x# such as, for example:
#2 and -2#

You get:
#f(x)=f(2)=1/2=0.5#
#f(-x)=f(-2)=-1/2=-0.5#

so basically we have that:

#f(-x)=-0.5=-f(x)#

giving an ODD function.