How do you determine p(c) given #p(x)=2x^2-x+1# and c=4?
1 Answer
Nov 14, 2016
Explanation:
Express p(x) in terms of c.
That is :
#p(color(blue)(c))=2color(blue)(c^2)-color(blue)(c)+1=2c^2-c+1# now substitute c = 4 into p(c)
#p(color(red)(4))=2(color(red)(4^2))-color(red)(4)+1#
#rArrp(4)=32-4+1=27#