# How do you determine p(c) given p(x)=2x^2-x+1 and c=4?

Nov 14, 2016

$p \left(4\right) = 27$

#### Explanation:

Express p(x) in terms of c.

That is : $p \left(\textcolor{b l u e}{c}\right) = 2 \textcolor{b l u e}{{c}^{2}} - \textcolor{b l u e}{c} + 1 = 2 {c}^{2} - c + 1$

now substitute c = 4 into p(c)

$p \left(\textcolor{red}{4}\right) = 2 \left(\textcolor{red}{{4}^{2}}\right) - \textcolor{red}{4} + 1$

$\Rightarrow p \left(4\right) = 32 - 4 + 1 = 27$