# How do you determine p(c) given p(x)=2x^3-x+6 and c=-3?

Aug 18, 2016

$- 45$

#### Explanation:

To calculate p(c) substitute x = c into f(x) and to evaluate when c = -3, substitute c = - 3 into p(c).

$\Rightarrow p \left(\textcolor{b l u e}{c}\right) = 2 {\textcolor{b l u e}{c}}^{3} - \textcolor{b l u e}{c} + 6$

and when c = -3

$\Rightarrow p \left(\textcolor{red}{- 3}\right) = 2 {\left(\textcolor{red}{- 3}\right)}^{3} - \left(\textcolor{red}{- 3}\right) + 6$

$\Rightarrow p \left(- 3\right) = - 54 + 3 + 6 = - 45$