How do you determine p(c) given #p(x)=4x^2-33x-180# and c=12?

1 Answer
Aug 31, 2016

#p(12)=0#

Explanation:

To determine p(c), substitute x = c into p(x).

#rArr p(color(red)(c))=4(color(red)(c))^2-33(color(red)(c))-180#

Thus #p(c)=4c^2-33c-180#

Similarly to evaluate p(c) when c = 12, substitute c = 12 into p(c)

#rArr p(color(red)(12))=4(color(red)(12))^2-33(color(red)(12))-180#

Hence #p(12)=(4xx144)-(33xx12)-180=0#