How do you determine p(c) given #p(x)=6x^4-x^2+2# and c=-2/3?

1 Answer
Jun 3, 2017

#p(-2/3)=74/27#

Explanation:

#" find p(c) by substituting x = c into p(x)"#

#rArrp(c)=6c^4-c^2+2#

#"find " p(-2/3)" by substituting " c=-2/3" into p(c)"#

#rArrp(color(red)(-2/3))=6(color(red)(-2/3))^4-(color(red)(-2/3))^2+2#

#color(white)(xxxxxxxx)=6xx16/81-4/9+2#

#color(white)(xxxxxxxx)=96/81-36/81+162/81#

#color(white)(xxxxxxxx)=222/81=74/27#