How do you determine p(c) given #p(x)=8x^3+12x^2+6x+1# and c=-1/2?
1 Answer
Aug 20, 2016
0
Explanation:
The first step is to obtain p(c). To do this substitute x = c into p(x).
#p(color(blue)(c))=8(color(blue)(c))^3+12(color(blue)(c))^2+6(color(blue)(c))+1=8c^3+12c^2+6c+1# We now have to evaluate p(c) when c
#=-1/2#
#p(color(red)(-1/2))=8(color(red)(-1/2))^3+12(color(red)(-1/2))^2+6(color(red)(-1/2))+1#
#rArrp(-1/2)=-1+3-3+1=0#
