How do you determine the binomial factors of x^3-5x^2-x+5?

Feb 2, 2017

$= \left(x - 5\right) \left(x - 1\right) \left(x + 1\right) .$

Explanation:

$\underline{{x}^{3} - 5 {x}^{2}} - \underline{x + 5}$

$= {x}^{2} \left(x - 5\right) - 1 \left(x - 5\right)$

$= \left(x - 5\right) \left({x}^{2} - 1\right)$

$= \left(x - 5\right) \left(x - 1\right) \left(x + 1\right) .$