# How do you determine the standard form of the equation of the line that passes through (-7,8) and (0,2)?

Jan 21, 2017

$7 y + 6 x - 14 = 0$.

#### Explanation:

If we know two coordinates of a line

$\left({x}_{1} , {y}_{1}\right) , \left({x}_{2} , {y}_{2}\right)$

then the eqn can be found using the formula;

$\frac{y - {y}_{1}}{{y}_{2} - {y}_{1}} = \frac{x - {x}_{1}}{{x}_{2} - {x}_{1}}$

in this case:

$\left({x}_{1} , {y}_{1}\right) = \left(- 7 , 8\right)$

$\left({x}_{2} , {y}_{2}\right) = \left(0 , 2\right)$

so: $\frac{y - 8}{2 - 8} = \frac{x - - 7}{0 - - 7}$

$\frac{y - 8}{-} 6 = \frac{x + 7}{7}$

$\implies 7 y - 56 = - 6 x - 42$

$7 y + 6 x - 14 = 0$.