How do you determine whether the graph of #f(x)=5x^2+6x+9# is symmetric with respect to the origin?
Not symmetric about O.
The graph of y = f(x) is symmetric with respect to the origin, if f(-x) = -
f(x) =-y. In other words, if (x, y) is on the graph, (-x, -y) has to be on
Here, f(x)=5x^2+6x+9 and f(-x)= 5x^2-6x+9 that is not
graph is not symmetric about O.
In polar form
symmetry about the pole. In other words, f(theta) should be periodic