How do you determine whether the graph of #g(x)=(x^2-1)/x# is symmetric with respect to the origin?

1 Answer
Feb 11, 2017

Answer:

The graph of g(x) is symmetric with respect to the origin

Explanation:

The graph of g(x) is symmetric with respect to the origin if

#g(-x)=-g(x)#

that's if g(x) is an odd function , then it is:

# **g(-x)** =((-x)^2-1)/(-x)=-(x^2-1)/x **=-g(x)** #

graph{(x^2-1)/x [-5, 5, -5, 5]}