How do you determine whether the graph of #y=1/x^2# is symmetric with respect to the x axis, y axis, the line y=x or y=-x, or none of these? Precalculus Functions Defined and Notation Symmetry 1 Answer Alan N. May 23, 2018 Answer: #y# is symmetric about the #y-#axis Explanation: #y=1/x^2# The graph below shows #y# with respect to the primary axes and #y=+-x# graph{(y-(1/x^2))(y-x)(y+x)=0 [-14.24, 14.23, -7.12, 7.11]} From which we can see that #y# has "mirror" symmetry about the #y-#axis. Related questions What functions have symmetric graphs? What are some examples of a symmetric function? What is a line of symmetry? What is rotational symmetry? Is the function #f(x) = x^2# symmetric with respect to the y-axis? Is the function #f(x) = x^2# symmetric with respect to the x-axis? Is the function #f(x) = x^3# symmetric with respect to the y-axis? What is the line of symmetry for #f(x) = x^4#? Is the graph of the function #f(x) = 2^x# symmetric? Is #f(x)=x^2+sin x# an even or odd function? See all questions in Symmetry Impact of this question 250 views around the world You can reuse this answer Creative Commons License