Question

How do you differentiate `2x sin x + x^2 cos x`?

Answer 1

I got: `y'=(2-x^2)sin(x)+4xcos(x)`

Explanation:

We can use the Product Rule to the two functions:
Consider it written as:
`y=(2x)*sin(x)+(x^2)*cos(x)`
we get:
`y'=2sin(x)+2xcos(x)+2xcos(x)-x^2sin(x)`
rearranging:
`y'=(2-x^2)sin(x)+4xcos(x)`