How do you differentiate #cos(x^2+5)#?

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Answer 1 · 2016-12-06T15:10:36

The answer is #=-2xsin(x^2+5)#

You use chain differentiation

If #y=cosu(x)#

#dy/dx=-sin(u(x))*u'(x)#

Here, #u(x)=x^2+5#

#u'(x)=2x#

So,

#(cos(x^2+5))'=-sin(x^2+5)*2x#