How do you differentiate #f(x)=(1+tan^2x)/secx#?

Question

6911 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-31T20:30:58

#f(x)=(1+tan^2x)/secx#

#=sec^2x/secx#

#=secx#

Which means that:

#f'(x)=secxtanx#

Watch this video to find out how to differentiate secx:

You may also need to see some handy trigonometric rules .