Question

How do you differentiate `f(x) = (2x-1)(3x-2)(5x+1)`?

Answer 1

There is one more method i.e. to take natural logarithms on both side and then differentiate with respect to X this will definitely simplify the calculation to much extent
`lnf (x)=ln (2x-1)+ ln (3x-2)+ln (5x+1)`
`=>(f'(x))/(f (x))=2/(2x-1) +3/(3x-2)+5 /(5x+1)`
`:.f'(x)=(2x-1)(3x-2)(5x+1)[2/(2x-1)+3/(3x-2)+5/(5x+1)]`