How do you differentiate #f(x)=2x^2*e^x*sinx# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer Jim S May 4, 2018 #2xe^x(2sinx+xsinx+xcosx)# Explanation: #f'(x)=(2x^2e^xsinx)'# #=# #(2x^2)'e^xsinx+2x^2(e^x)'sinx+2x^2e^x(sinx)'# #=# #4xe^xsinx+2x^2e^xsinx+2x^2e^xcosx# #=# #2xe^x(2sinx+xsinx+xcosx)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1733 views around the world You can reuse this answer Creative Commons License