Question

How do you differentiate `f(x) =2x^4 * 6^(3x)` using the product rule?

Answer 1

`f'(x)=8x^3*6^(3x)+6x^4*6^(3x)*ln(6)`

Explanation:

Not that
`(a^x)'=a^x*ln(a)`
for `a>0`
so we get
`f'(x)=8x^3*6^(3x)+6x^4*6^(3x)*ln(6)`