Question

How do you differentiate `f(x)= (4x^2-1) *ln x` using the product rule?

Answer 1

`y'=(4x^2-1)*1/x+lnx*8x`

Explanation:

The product Rule:

`color(red)[y=f(x)*g(x)]`

`color(red)[y'=f(x)*g'(x)+g(x)*f'(x)]`

now lets derive `color(blue)[y= (4x^2-1) *ln x]`

`y'=(4x^2-1)*1/x+lnx*8x`