Question

How do you differentiate # f(x) = arctan(1/(1+x^2)) #?

Answer 1

`f'(x) = 1/(1+(1/(1+x^2))^2 ) *-(2x)/(1+x^2)^2`

Explanation:

`f'(u)=1/(1+u^2) * u'`
`f'(x) = 1/(1+(1/(1+x^2))^2 ) *-1/(1+x^2)^2 (2x)`
`f'(x) = 1/(1+(1/(1+x^2))^2 ) -(2x)/(1+x^2)^2`