How do you differentiate #f(x)=(-e^x+secx)(3x^3-x)# using the product rule?
1 Answer
Jan 20, 2016
Explanation:
Product rule states that the derivative of a function
#f'(x)=g'(x)h(x)+g(x)h'(x)#
In this particular case, we have
#g(x)=-e^x+secx#
#h(x)=3x^3-x#
#g'(x)=-e^x+secxtanx#
#h'(x)=9x^2-1#
Applying this, we see that
#f'(x)=(secxtanx-e^x)(3x^3-x)+(secx-e^x)(9x^2-1)#
