Question

How do you differentiate `f(x)=ln2x * cot5x` using the product rule?

Answer 1

`(1/x) cot 5x +5 ln2x sec^2 5x`

Explanation:

It can be done using product rule of differentiation (fg)'= f'g +fg'
Accordingly, required derivative would be`(1/(2x)) (2) cot 5x + ln2x sec^2 5x (5)`

=`(1/x) cot 5x +5 ln2x sec^2 5x`